Square Root Of 5 12 Iota Methods for square root of a complex number Let z 5 12 i x i y squaring x 2 y 2 2 i x y 5 12 i
The square root of 5 12i is Q10 If x 3 5 i 2 then the value of 2x3 6x2 17x 12 is e cos 2 x cos 4 x cos 6 x log c 2 Three parallel lines 2 and 3 are drawn through the vertices A B and C of a square ABCD If the distance between 1 and 2 is 7 and between 2 and 3 is 12 then the area of the
Square Root Of 5 12 Iota
Square Root Of 5 12 Iota
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SQUARE ROOT OF IOTA MMF YouTube
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Square Root Of Iota I 1 2 YouTube
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Iota has two square roots just like all non zero complex numbers The value of the square root of iota given as i can be calculated using De Moivre s Theorem We know that i cos 2 isin 2 cos 2 2n isin 2 2n n Find an answer to your question find the square root of the following 5 12 iota
According to the problem we need to find the square root of the complex number 5 12i Let us assume the square root of the given complex number 5 12i be a bi So we get 16 2k Explanation First use the distributive property and split the root 512 x k 2 So k 2 k Since 512 is a cube number rather than a square number if halved it s equal to 256 So again
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Write the values of the square root of i If x iy sqrt frac a ib c id then write the value of x 2 y 2 2 If sqrt a ib x iy then possible value of sqrt a ib is Find square root of 12 5i Find square root of a complex number 12 minus 5 iota
Therefore the square root of 5 12i can be 3 2i or 3 2i Hence option 1 is correct 5 12i 2 3i Was this answer helpful Find the square root of 5 12i Find the modulus argument and the principal argument of the complex numbers
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Methods for square root of a complex number Let z 5 12 i x i y squaring x 2 y 2 2 i x y 5 12 i
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The square root of 5 12i is Q10 If x 3 5 i 2 then the value of 2x3 6x2 17x 12 is e cos 2 x cos 4 x cos 6 x log c 2
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Square Root Of 5 12 Iota - Find an answer to your question find the square root of the following 5 12 iota
