184 Divided By 2 Divide 184 into two parts such that one third of one part may exceed one seventh of other part by 8 Let one part be x then other part will be 184 x One third of x 3 x One seventh of other part 7 184 x According to the question 3 x 7 184 x 8 3 x 7 184 x 56 7x 3 240 x 7x 720 3x 10x 720
Divide 184 into 2 parts such that one third of one part may exceed one seventh of the other by 8 208511 Harneetkaur Harneetkaur 18 10 2015 The 2 parts are 72 and 112 Step by step explanation Let the 2 parts be x and y Sum of parts 184 x y 1 According To Question One third of one part may exceed one seventh of another part by 8 x 3 y 7 8 7x 3y 168 2 From 1 x y 184 y 184 x Using the value of y in 2
184 Divided By 2
184 Divided By 2
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5 150 Divided By 2 With Solution Brainly ph
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Solution Let the one part be x then the other part will be 184 x According to the question 1 3rd of one part may exceed 1 7th of the other part by 8 1 3 x If 184 is divided into two parts such that one third of one part exceeds one seventh of the other part by 8 then the greater part is A 72 B 110 C 61234
Given that 184 is divided into two parts x y 184 x 184 y 1 ii Given that one third of one part exceeds one seventh of other part by 8 1 3 x 1 7 y 8 LCM of 3 7 21 7x 3y 168 7 184 y 3y 168 1288 7y 3y 168 1288 168 10y 1120 10y y 112 Substitute y Now let s find the values of x and y that satisfy this equation and sum up to 184 Since 7x 3y 168 we can rewrite it as y 7x 168 3 Now we know x y 184 so we substitute y with the expression we found x 7x 168 3 184 To solve for x we ll first multiply the whole equation by 3 to eliminate the fraction 3x 7x
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Divide 184 into two parts such that one third of one part may exceed one seventh of other part by 8 Let one part be x then other part will be 184 x One third of x 3 x One seventh of other part 7 184 x According to the question 3 x 7 184 x 8 3 x 7 184 x 56 7x 3 240 x 7x 720 3x 10x 720
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Divide 184 into 2 parts such that one third of one part may exceed one seventh of the other by 8 208511 Harneetkaur Harneetkaur 18 10 2015
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184 Divided By 2 - [desc-14]
