60 Divided By 40

60 Divided By 40 The smallest number when divided by 30 40 60 leaving the same remainder 7 in each case Solution Now let us find the LCM of these three numbers 30 2 3 5

The given number is 60 To find We have to divide it into the ratio of 2 3 Solution The ratio is 2 3 Let one part of 60 is 2x and another is 3x So the total is 2x 3x 5x 5x is 40 2 2 2 5 60 2 2 3 5 LCM is the product of maximum frequencies of all the factors of given numbers LCM 2 2 2 3 5 5 600 The required number

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60 Divided By 40
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The given numbers are 40 50 and 60 The remainder is 5 in each case Solution First we will find the LCM of the given numbers 40 50 and 60 by prime factorization method 60 divided by half plus 10 is 130 Step by step explanation Given data 60 divided by half plus 10 Convert verbal statement into algebraic statement Using BODMAS rule first

Smallest common multiple of 40 50 and 60 L C M of 40 50 60 600 Since we have to find the number when divided by 40 50 60 leaves the remainder 5 we have add 5 to 600 Least common multiple of 30 40 and 60 is 120 which means that 120 is the smallest number which when divided by 30 40 and 60 leaves 0 as the remainder Thus If we add 7 to 120 we

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Lcm of 25 40 60 600 given it leaves a remainder of 7 So the number is 600 7 607 therefore 607 is the smallest no which when divided by 25 50 and 60 leaves a LCM of 25 40 60 2 2 2 5 5 3 8 25 3 200 3 600 600 perfectly divides the 3 numbers and leaves the remainder as 0 So 600 8 608 is the smallest number which leaves

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Find The Smallest Number Which When Divided By 30 40 And 60

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The smallest number when divided by 30 40 60 leaving the same remainder 7 in each case Solution Now let us find the LCM of these three numbers 30 2 3 5

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Divide 60 In The Ratio Of 2 3 Brainly

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The given number is 60 To find We have to divide it into the ratio of 2 3 Solution The ratio is 2 3 Let one part of 60 is 2x and another is 3x So the total is 2x 3x 5x 5x is

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