Hawaiian Cocktail Drinks I am not sure how to create placeholders in Postgres I did some research I found some posts on Stackoverflow and tutorials on Postgres that suggested I used 1 2 or use
It s a little bit confusing You say the code you ve provided in your post is intended to execute when a button is clicked correct This means that you ve already replied to a slash Here is simple example what I tried to do I can t get f string to work in my case to use it as table name placeholder and I can t figure it out what you are suggesting I m
Hawaiian Cocktail Drinks
Hawaiian Cocktail Drinks
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The character after the at sign in the placeholder key is the transformation that is applied to the argument before inserting it into the placeholder S for raw SQL I for Identifiers Technically you have the right amount but you re missing parentheses and commas and it s broken up throughout your query which I suspect is confusing SQL Just like
In Postgres the value placeholder is which one is recommend when the value is the same reusing the value placeholder or not db Exec INSERT Now I want to do the same thing via inline queries so that queries can be made through any chat Have used the setinline command and set a placeholder which appears
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It only seems to be these two lines as I have other queries with LIKE statements that work no issue I have other commands with a s placeholder in the middle and a LIKE I m trying to connect to Sage 50 using pyodbc I m able to get my data out if I input the bank account directly into the sql query however if I try to insert the value into the query I
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https://www.reddit.com › PostgreSQL › comments › nuzlro › how_to_use…
I am not sure how to create placeholders in Postgres I did some research I found some posts on Stackoverflow and tutorials on Postgres that suggested I used 1 2 or use
https://www.reddit.com › Discordjs › comments › xmrisk › edit_button_la…
It s a little bit confusing You say the code you ve provided in your post is intended to execute when a button is clicked correct This means that you ve already replied to a slash
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